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python迭代算法

2022-05-21 20:48| 来源: 网络整理| 查看: 265

本文主要和大家分享Python迭代模式实例详解,主要以代码的形式和大家分享,希望能帮助到大家。# -*- coding: utf-8 -*-

"""

Created on Thu Mar 29 11:43:05 2018

@author: mz

"""

class Iterator(object):

def Next(self):

pass

def HasNext(self):

pass

def First(self):

pass

def Forward(self):

pass

class CocreteIterator(Iterator):

def __init__(self, aggregate):

self._aggregate = aggregate

def Next(self):

return self._aggregate.Next()

def HasNext(self):

return self._aggregate.HasNext()

def First(self):

return self._aggregate.First()

def Forward(self):

return self._aggregate.Forward()

class Aggregate(object):

def CreateIterator(self):

pass

def Next(self):

pass

def HasNext(self):

pass

def First(self):

pass

def Attach(self, obj):

pass

def Forward(self):

pass

class ConcreteAggregate(object):

def __init__(self):

self._lst = []

self._index = 0

def CreateIterator(self):

return CocreteIterator(self)

def Next(self):

return self._lst[self._index]

def HasNext(self):

return self._index < len(self._lst)

def First(self):

self._index = 0

return self._lst[0]

def Attach(self, obj):

self._lst.append(obj)

def Forward(self):

self._index += 1

if "__main__" == __name__:

aggregate = ConcreteAggregate()

aggregate.Attach(1)

aggregate.Attach("2")

aggregate.Attach("a")

aggregate.Attach("b")

aggregate.Attach("c")

aggregate.Attach("45")

it = aggregate.CreateIterator()

while it.HasNext():

print(it.Next())

it.Forward()

运行结果:1

2

a

b

c

45



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