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方法适合于任何台式机笔记本 Apex机器码-逃离塔科夫机器码均可彻底解决! 用心仔细看下方即可! Kslcckxpkc-可观看教程 void menu() { printf("********************\n"); printf("****** 1.play ******\n"); printf("****** 0.exit ******\n"); printf("********************\n"); } void SetMine(char mine[ROWS][COLS], int row, int col) { int count = EASY_COUNT; while (count) { int x = rand() % row + 1; int y = rand() % col + 1; if (mine[x][y] =='0') { mine[x][y] = '1'; count--; static int get_mine_count(char mine[ROWS][COLS], int x, int y) InitBoard(mine, ROWS, COLS, '0'); InitBoard(show, ROWS, COLS, '*');// DisplayBoard(mine, ROW, COL); DisplayBoard(show, ROW, COL); nt main() { int input = 0; do { menu(); printf(":>"); scanf("%d", &input); switch (input) { case 1: game();//实现游戏的函数 break; case 0: printf("\n"); break; default: printf("n"); break; } } while (input); return 0; void InitBoard(char board[ROWS][COLS], int rows, int cols, char set) { int i = 0; int j = 0; for (i = 0; i < rows; i++) { for (j = 0; j < cols; j++) { board[i][j] = set; } } #define ROW 9 #define COL 9 } void DisplayBoard(char board[ROWS][COLS], int row, int col) { int i = 0; int j = 0; { return mine[x - 1][y - 1] + mine[x - 1][y] + mine[x - 1][y + 1] + mine[x][y - 1] + mine[x][y + 1] + mine[x + 1][y - 1] + mine[x + 1][y] + mine[x + 1][y + 1] - 8 * '0'; if (win == row * col - EASY_COUNT) { printf("KCX,ckx!\n"); DisplayBoard(mine, ROW, COL); |
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