How many bytes are needed for a Chinese character in a 24*24 dot matrix?

Each character in the 24 dot matrix requires 24*24=576 points to save. Each byte in the computer is 8 bits. If one point in the dot matrix is ​​stored in one bit, a Chinese character dot matrix It requires 576/8=72 bytes.

The operating environment of this tutorial: Windows 7 system, Dell G3 computer.

Each word in the 24-dot matrix requires 24*24=576 points to save. Each byte in the computer is 8 bits. Each bit can save 1 point of information, so 576/8=72 words. Festival.

24X24 lattice, if one point in the lattice is stored with one bit, a Chinese character lattice requires 24 X 72 = 7200 bytes.

One Chinese character = 2 English letters = 2 bytes.

The official standard is: 1 Chinese character = 2 bytes, 1 byte (Byte) = 8 bits = 8 binary numbers, 1 bit (bit) = 1 binary number.

Hardware vendor standards are: 1GB=1000MB, 1MB=1000KB, 1KB=1000B.

Normally, B is called a byte, b is called a word bit, KB is called a kilobyte, MB is called a megabyte, and GB is called a gigabyte.

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