计算经纬度、距离、方位角 |
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1.根据两点经纬度计算其间距离，发现有3种公式，结果区别不是很大。 2.根据一点的经纬度与到另外一点的距离、方位角，计算另一点的经纬度，误差不是很大。 package com.zhs.util; /** * * 计算经纬度、距离、方位角 * * @author longge * @time 2016-06-02 * */ public class CalculationLogLatDistance { /** * 地球赤道半径(km) * */ public final static double EARTH_RADIUS = 6378.137; /** * 地球每度的弧长(km) * */ public final static double EARTH_ARC = 111.199; /** * 转化为弧度(rad) * */ public static double rad(double d) { return d * Math.PI / 180.0; } /** * 求两经纬度距离 * * @param lon1 * 第一点的经度 * @param lat1 * 第一点的纬度 * @param lon2 * 第二点的经度 * @param lat2 * 第二点的纬度 * @return 两点距离，单位km * */ public static double GetDistanceOne(double lon1, double lat1, double lon2, double lat2) { double r1 = rad(lat1); double r2 = rad(lon1); double a = rad(lat2); double b = rad(lon2); double s = Math.acos(Math.cos(r1) * Math.cos(a) * Math.cos(r2 - b) + Math.sin(r1) * Math.sin(a)) * EARTH_RADIUS; return s; } /** * 求两经纬度距离(google maps源码中) * * @param lon1 * 第一点的经度 * @param lat1 * 第一点的纬度 * @param lon2 * 第二点的经度 * @param lat2 * 第二点的纬度 * @return 两点距离，单位km * */ public static double GetDistanceTwo(double lon1, double lat1, double lon2, double lat2) { double radLat1 = rad(lat1); double radLat2 = rad(lat2); double a = radLat1 - radLat2; double b = rad(lon1) - rad(lon2); double s = 2 * Math.asin(Math.sqrt(Math.pow(Math.sin(a / 2), 2) + Math.cos(radLat1) * Math.cos(radLat2) * Math.pow(Math.sin(b / 2), 2))); s = s * EARTH_RADIUS; return s; } /** * 求两经纬度距离 * * @param lon1 * 第一点的经度 * @param lat1 * 第一点的纬度 * @param lon2 * 第二点的经度 * @param lat2 * 第二点的纬度 * @return 两点距离，单位km * */ public static double GetDistanceThree(double lon1, double lat1, double lon2, double lat2) { double radLat1 = rad(lat1); double radLat2 = rad(lat2); double radLon1 = rad(lon1); double radLon2 = rad(lon2); if (radLat1 < 0) radLat1 = Math.PI / 2 + Math.abs(radLat1);// south if (radLat1 > 0) radLat1 = Math.PI / 2 - Math.abs(radLat1);// north if (radLon1 < 0) radLon1 = Math.PI * 2 - Math.abs(radLon1);// west if (radLat2 < 0) radLat2 = Math.PI / 2 + Math.abs(radLat2);// south if (radLat2 > 0) radLat2 = Math.PI / 2 - Math.abs(radLat2);// north if (radLon2 < 0) radLon2 = Math.PI * 2 - Math.abs(radLon2);// west double x1 = Math.cos(radLon1) * Math.sin(radLat1); double y1 = Math.sin(radLon1) * Math.sin(radLat1); double z1 = Math.cos(radLat1); double x2 = Math.cos(radLon2) * Math.sin(radLat2); double y2 = Math.sin(radLon2) * Math.sin(radLat2); double z2 = Math.cos(radLat2); double d = Math.pow((x1 - x2), 2) + Math.pow((y1 - y2), 2) + Math.pow((z1 - z2), 2); // // 余弦定理求夹角 // double theta = Math.acos((2 - d) / 2); d = Math.pow(EARTH_RADIUS, 2) * d; // //余弦定理求夹角 double theta = Math.acos((2 * Math.pow(EARTH_RADIUS, 2) - d) / (2 * Math.pow(EARTH_RADIUS, 2))); double dist = theta * EARTH_RADIUS; return dist; } /** * 求两经纬度方向角 * * @param lon1 * 第一点的经度 * @param lat1 * 第一点的纬度 * @param lon2 * 第二点的经度 * @param lat2 * 第二点的纬度 * @return 方位角，角度（单位：°） * */ public static double GetAzimuth(double lon1, double lat1, double lon2, double lat2) { lat1 = rad(lat1); lat2 = rad(lat2); lon1 = rad(lon1); lon2 = rad(lon2); double azimuth = Math.sin(lat1) * Math.sin(lat2) + Math.cos(lat1) * Math.cos(lat2) * Math.cos(lon2 - lon1); azimuth = Math.sqrt(1 - azimuth * azimuth); azimuth = Math.cos(lat2) * Math.sin(lon2 - lon1) / azimuth; azimuth = Math.asin(azimuth) * 180 / Math.PI; if (Double.isNaN(azimuth)) { if (lon1 < lon2) { azimuth = 90.0; } else { azimuth = 270.0; } } return azimuth; } /** * 已知一点经纬度A，和与另一点B的距离和方位角，求B的经纬度(计算结果有误) * * @param lon1 * A的经度 * @param lat1 * A的纬度 * @param distance * AB距离（单位：米） * @param azimuth * AB方位角 * @return B的经纬度 * */ public static String GetOtherPoint(double lon1, double lat1, double distance, double azimuth) { azimuth = rad(azimuth); double ab = distance / EARTH_ARC;// AB间弧线长 ab = rad(ab); double Lat = Math.asin(Math.sin(lat1) * Math.cos(ab) + Math.cos(lat1) * Math.sin(ab) * Math.cos(azimuth)); double Lon = lon1 + Math.asin(Math.sin(azimuth) * Math.sin(ab) / Math.cos(Lat)); System.out.println(Lon + "," + Lat); double a = Math.acos(Math.cos(90 - lon1) * Math.cos(ab) + Math.sin(90 - lon1) * Math.sin(ab) * Math.cos(azimuth)); double C = Math.asin(Math.sin(ab) * Math.sin(azimuth) / Math.sin(a)); System.out.println("c=" + C); double lon2 = lon1 + C; double lat2 = 90 - a; return lon2 + "," + lat2; } /** * 已知一点经纬度A，和与另一点B的距离和方位角，求B的经纬度 * * @param lon1 * A的经度 * @param lat1 * A的纬度 * @param distance * AB距离（单位：米） * @param azimuth * AB方位角 * @return B的经纬度 * */ public static String ConvertDistanceToLogLat(double lng1, double lat1, double distance, double azimuth) { azimuth = rad(azimuth); // 将距离转换成经度的计算公式 double lon = lng1 + (distance * Math.sin(azimuth)) / (EARTH_ARC * Math.cos(rad(lat1))); // 将距离转换成纬度的计算公式 double lat = lat1 + (distance * Math.cos(azimuth)) / EARTH_ARC; return lon + "," + lat; } public static void main(String[] args) { double lon1 = 121.469156; double lat1 = 31.232307; double lon2 = 121.469156; double lat2 = 31.233205; double distance = GetDistanceTwo(lon1, lat1, lon2, lat2); double azimuth = GetAzimuth(lon1, lat1, lon2, lat2); System.out.println("经纬度为(" + lon1 + "," + lat1 + ")的点与经纬度为(" + lon2 + "," + lat2 + ")相距：" + distance + "千米," + "方位角：" + azimuth + "°"); System.out.println("距经纬度为(" + lon1 + "," + lat1 + ")的点" + distance + "千米,方位角为" + azimuth + "°的另一点经纬度为(" + ConvertDistanceToLogLat(lon1, lat1, distance, azimuth) + ")"); } }
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