openlayers系列之根据一个坐标为中心绘制正方形 |
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openlayers系列之根据一个坐标为中心绘制正方形
2023-03-28
约 855 字
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需求
最近有个需求,就是要根据实时坐标点进行正方形打点。那就简单的实现下。 按需引入 1 2 3 4 5 6 7 8 9 10 import Map from 'ol/Map'; import View from 'ol/View'; import XYZ from 'ol/source/XYZ'; import { Tile as TileLayer } from 'ol/layer'; import { fromLonLat, transform } from "ol/proj"; import { Polygon } from "ol/geom"; import { Feature } from "ol"; import { Style, Fill } from "ol/style"; import VectorLayer from "ol/layer/Vector"; import { Vector as VectorSource } from "ol/source"; 根据经纬度返回经度半径 1 2 3 4 5 6 lngradius(latitude, raidusMile) { var degree = (24901 * 1609) / 360.0; var mpdLng = degree * Math.cos(latitude * (Math.PI / 180)); var dpmLng = 1 / mpdLng; return dpmLng * raidusMile; } 根据经纬度返回纬度半径 1 2 3 4 5 latradius(raidusMile) { var degree = (24901 * 1609) / 360.0; var dpmLat = 1 / degree; return dpmLat * raidusMile; } 根据经纬度为中心计算出正方形4个点的经纬度 1 2 3 4 5 6 7 8 9 getlnglat(longitude = 113.90314496806384, latitude = 32.55119145031371, raidusMile = 1000) { var radiusLat = this.latradius(raidusMile); var minLat = latitude - radiusLat; var maxLat = latitude + radiusLat; var radiusLng = this.lngradius(latitude, raidusMile); var minLng = longitude - radiusLng; var maxLng = longitude + radiusLng; return [[maxLng, minLat], [maxLng, maxLat], [minLng, maxLat], [minLng, minLat], [maxLng, minLat]] } 生成正方形 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 addsq(arr) { let lineStringLayer = new VectorLayer({ source: new VectorSource(), style: new Style({ fill: new Fill({ color: 'rgba(90,159,221,.5)' }), }), }); let arr2 = [] arr.forEach(el => { arr2.push(fromLonLat(el)) }) this.arrr = arr2 let feature = new Feature({ geometry: new Polygon([arr2]), }) lineStringLayer.getSource().addFeature( feature ); this.map.addLayer(lineStringLayer); } 地图初始化添加正方形 1 this.addsq(this.getlnglat()) 效果如下 整体代码如下 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45 46 47 48 49 50 51 52 53 54 55 56 57 58 59 60 61 62 63 64 65 66 67 68 69 70 71 72 73 74 75 76 77 78 79 80 81 82 83 84 85 86 87 88 89 90 91 92 93 94 95 96 97 98 99 100 101 102 103 104 105 106 107 108 109 110 111 112 113 114 115 import Map from 'ol/Map'; import View from 'ol/View'; import XYZ from 'ol/source/XYZ'; import { Tile as TileLayer } from 'ol/layer'; import { fromLonLat, transform } from "ol/proj"; import { Polygon } from "ol/geom"; import { Feature } from "ol"; import { Style, Fill } from "ol/style"; import VectorLayer from "ol/layer/Vector"; import { Vector as VectorSource } from "ol/source"; export default { name: 'HelloWorld', data() { return { map: null, popup: null, pointLayer: null } }, mounted() { this.init(); }, methods: { init() { let baseLayer = new TileLayer({ visible: true, name: "电子图", source: new XYZ({ url: 'https://wprd0{1-4}.is.autonavi.com/appmaptile?lang=zh_cn&size=1&style=7&x={x}&y={y}&z={z}', crossOrigin: "anonymous", }), }); this.map = new Map({ target: 'map', layers: [baseLayer], view: new View({ center: fromLonLat([113.90314496806384, 32.55119145031371]), zoom: 16 }) }); this.addsq(this.getlnglat()) }, // 返回经度半径 lngradius(latitude, raidusMile) { var degree = (24901 * 1609) / 360.0; var mpdLng = degree * Math.cos(latitude * (Math.PI / 180)); var dpmLng = 1 / mpdLng; return dpmLng * raidusMile; }, // 返回纬度半径 latradius(raidusMile) { var degree = (24901 * 1609) / 360.0; var dpmLat = 1 / degree; return dpmLat * raidusMile; }, // 根据经纬度为中心计算出正方形4个点的经纬度 getlnglat(longitude = 113.90314496806384, latitude = 32.55119145031371, raidusMile = 1000) { var radiusLat = this.latradius(raidusMile); var minLat = latitude - radiusLat; var maxLat = latitude + radiusLat; var radiusLng = this.lngradius(latitude, raidusMile); var minLng = longitude - radiusLng; var maxLng = longitude + radiusLng; return [[maxLng, minLat], [maxLng, maxLat], [minLng, maxLat], [minLng, minLat], [maxLng, minLat]] }, // 添加正方格 addsq(arr) { let lineStringLayer = new VectorLayer({ source: new VectorSource(), style: new Style({ fill: new Fill({ color: 'rgba(90,159,221,.5)' }), }), }); let arr2 = [] arr.forEach(el => { arr2.push(fromLonLat(el)) }) this.arrr = arr2 let feature = new Feature({ geometry: new Polygon([arr2]), }) lineStringLayer.getSource().addFeature( feature ); this.map.addLayer(lineStringLayer); }, } } #map { width: 1920px; height: 1080px; }文章作者 valiant 上次更新 2023-03-28 openlayers |
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