第一种转换方式:
1 --> 一
12 --> 一二
def num_to_char(num):
"""数字转中文"""
num=str(num)
new_str=""
num_dict={"0":u"零","1":u"一","2":u"二","3":u"三","4":u"四","5":u"五","6":u"六","7":u"七","8":u"八","9":u"九"}
listnum=list(num)
# print(listnum)
shu=[]
for i in listnum:
# print(num_dict[i])
shu.append(num_dict[i])
new_str="".join(shu)
# print(new_str)
return new_str
第二种转换方式:
1 --> 一
12 --> 十二
23 --> 二十三
_MAPPING = (u'零', u'一', u'二', u'三', u'四', u'五', u'六', u'七', u'八', u'九', u'十', u'十一', u'十二', u'十三', u'十四', u'十五', u'十六', u'十七',u'十八', u'十九')
_P0 = (u'', u'十', u'百', u'千',)
_S4 = 10 ** 4
def _to_chinese4(num):
assert (0 = 10:
lst.append(num % 10)
num = num / 10
lst.append(num)
c = len(lst) # 位数
result = u''
for idx, val in enumerate(lst):
val = int(val)
if val != 0:
result += _P0[idx] + _MAPPING[val]
if idx < c - 1 and lst[idx + 1] == 0:
result += u'零'
return result[::-1]
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