How do you convert emu/g to Ub (mewB) per TM atom? https://www.researchgate.net/pos ... Ub_mewB_per_TM_atom 1 emu = 10^-3 J/T 1 μB = 9.27402×10^-24 J/T So, 1 emu = 10^-3/9.27402×10^-24 μB = 1.0783×10^20 μB Now you have to know the formula of the composite and gm. Atomic wt. of each element…. Suppose… Ni_2MnGa…….. Ni = 58.6934 Mn = 54.938 Ga = 69.723 1 Ni atom = 58.6934/6.022×10^23 g = 9.7465×10^-23 g 1 Mn atom = 54.938/6.022×10^23 g = 9.1229×10^-23 g 1 Ga atom = 69.723/6.022×10^23 g = 11.5781×10^-23 g So, mass of 1 formula unit (f.u.) Ni2MnGa = (2×9.7465+9.1229+11.5781)×10^-23 g = 4.0194×10^-22 g Suppose, Ms of Ni_2MnGa = 80 emu/g Then, moment for 1 f.u. can be given as:::: = 80×4.0194×10^-22 emu = 3.2156×10^-20 emu = 3.2156×10^-20×1.0783×10^20 μB (using the conversion given in 3rd line) = 3.4674 μB So, Ms = 3.5 μB/f.u，