编程:计算1~100的累加和,结果存放在内部RAM的30H、31H中,低位字节在前。 悬赏分:100 - 解决时间:2009-11-29 20:22 --------------------------------------最佳答案:;下列程序,经过仿真调试,结果是:(30H)=BAH, (31H)=13H;程序如下: MOV 30H, #0 MOV 31H, #0 MOV DPTR, #1 MOV R2, #10LOOP1: MOV R3, #10LOOP2: MOV A, 30H ADD A, DPL MOV 30H, A MOV A, 31H ADDC A, DPH MOV 31H, A INC DPTR DJNZ R3, LOOP2 DJNZ R2, LOOP1 RET;完 ------------回答者: 做而论道 - 十一级 2009-11-29 20:05 ------------提问者对于答案的评价: O(∩_∩)O 谢谢~真的===========================================#includevoid main(){ int sum = 0; char i; char *s1 = 0x30, *s2 = 0x31; //s1 = 0x30, s2 = 31 //;指针指向RAM中地址 for(i = 0; i |