用C语言写一个可以选择关卡添加关卡的小游戏,推箱子

2024-07-11 15:00| 来源: 网络整理| 查看: 265

目录关于用C语言写一个可以选择关卡的小游戏代码部分所有代码Tui_Xiang_Zi.hTui_Xiang_Zi.cpp关卡数据关卡数据规则思路和建议建议警告

关于用C语言写一个可以选择关卡的小游戏

这个小游戏就是大家熟知的推箱子，废话不多说先上效果图在这里插入图片描述

上面的五角星就是玩家的位置，红色的箱子就是已经放到指定位置的样子，黄色的箱子是还没有在指定位置的箱子，黑色的方框就是黄色箱子该放置的位置，然后我们使用↑↓←→来操作我们的五角星也就是我们的玩家位置

代码部分所有代码 Tui_Xiang_Zi.h #include #include #include #include #include #define MAXSIZE 20 #define MAXSIZE2 15 typedef struct Tui_Xiang_Zi { //我的 x y 目标点 x y 长宽 // 剩余目标点数总目标点数 int p_Now, p_Zong, mx, my, X1[MAXSIZE2], Y1[MAXSIZE2], Kuan, Chang; int map_Data[MAXSIZE][MAXSIZE]; } Guan_Ka; //初始化分配内存 void Initialization(Guan_Ka *&s) { s = (Guan_Ka *)malloc(sizeof(Guan_Ka)); //以下内容为初始化数据 s->my = s->mx = s->Kuan = s->Chang = s->p_Now = s->p_Zong = 0; for (int i = 0; i for (int n = 0; n free(s); } //读取关卡 int read_Guan_ka(char Guan[2], Guan_Ka *&s) { FILE *fp; int c, k; char fpp[] = {"./Tui_Xiang_zi01.txt"}; fpp[14] = Guan[0]; fpp[15] = Guan[1]; if ((fp = fopen(fpp, "r")) == NULL) { return 0; } c = (int)fgetc(fp) - 48; s->Chang = c * 10 + (int)fgetc(fp) - 48; k = (int)fgetc(fp) - 48; s->Kuan = k * 10 + (int)fgetc(fp) - 48; for (int i = 0; i Kuan; i++) { for (int n = 0; n Chang; n++) { s->map_Data[i][n] = (int)fgetc(fp) - 48; //数据检查使用时请注释上行解释下行 //printf("%d",s->map_Data[i][n] =(int)fgetc(fp) - 48); } } fclose(fp); return 1; } //上移操作 void up(Guan_Ka *&s) { if (s->map_Data[s->my - 2][s->mx - 1] == 1) { return; } else if (s->map_Data[s->my - 2][s->mx - 1] == 4 || s->map_Data[s->my - 2][s->mx - 1] == 3) { if (s->map_Data[s->my - 3][s->mx - 1] == 2 || s->map_Data[s->my - 3][s->mx - 1] == 0) { s->map_Data[s->my - 3][s->mx - 1] = s->map_Data[s->my - 2][s->mx - 1]; s->map_Data[s->my - 2][s->mx - 1] = 0; s->map_Data[s->my - 2][s->mx - 1] = s->map_Data[s->my - 1][s->mx - 1]; s->map_Data[s->my - 1][s->mx - 1] = 0; s->my--; } } else { s->map_Data[s->my - 2][s->mx - 1] = s->map_Data[s->my - 1][s->mx - 1]; s->map_Data[s->my - 1][s->mx - 1] = 0; s->my--; } } //下移操作 void down(Guan_Ka *&s) { if (s->map_Data[s->my][s->mx - 1] == 1) { return; } else if (s->map_Data[s->my][s->mx - 1] == 4 || s->map_Data[s->my][s->mx - 1] == 3) { if (s->map_Data[s->my + 1][s->mx - 1] == 2 || s->map_Data[s->my + 1][s->mx - 1] == 0) { s->map_Data[s->my + 1][s->mx - 1] = s->map_Data[s->my][s->mx - 1]; s->map_Data[s->my][s->mx - 1] = 0; s->map_Data[s->my][s->mx - 1] = s->map_Data[s->my - 1][s->mx - 1]; s->map_Data[s->my - 1][s->mx - 1] = 0; s->my++; } } else { s->map_Data[s->my][s->mx - 1] = s->map_Data[s->my - 1][s->mx - 1]; s->map_Data[s->my - 1][s->mx - 1] = 0; s->my++; } } // 左移操作 void left(Guan_Ka *&s) { if (s->map_Data[s->my - 1][s->mx - 2] == 1) { return; } else if (s->map_Data[s->my - 1][s->mx - 2] == 4 || s->map_Data[s->my - 1][s->mx - 2] == 3) { if (s->map_Data[s->my - 1][s->mx - 3] == 2 || s->map_Data[s->my - 1][s->mx - 3] == 0) { s->map_Data[s->my - 1][s->mx - 3] = s->map_Data[s->my - 1][s->mx - 2]; s->map_Data[s->my - 1][s->mx - 2] = 0; s->map_Data[s->my - 1][s->mx - 2] = s->map_Data[s->my - 1][s->mx - 1]; s->map_Data[s->my - 1][s->mx - 1] = 0; s->mx--; } } else { s->map_Data[s->my - 1][s->mx - 2] = s->map_Data[s->my - 1][s->mx - 1]; s->map_Data[s->my - 1][s->mx - 1] = 0; s->mx--; } } // 右移操作 void right(Guan_Ka *&s) { if (s->map_Data[s->my - 1][s->mx] == 1) { return; } else if (s->map_Data[s->my - 1][s->mx] == 4 || s->map_Data[s->my - 1][s->mx] == 3) { if (s->map_Data[s->my - 1][s->mx + 1] == 2 || s->map_Data[s->my - 1][s->mx + 1] == 0) { s->map_Data[s->my - 1][s->mx + 1] = s->map_Data[s->my - 1][s->mx]; s->map_Data[s->my - 1][s->mx] = 0; s->map_Data[s->my - 1][s->mx] = s->map_Data[s->my - 1][s->mx - 1]; s->map_Data[s->my - 1][s->mx - 1] = 0; s->mx++; } } else { s->map_Data[s->my - 1][s->mx] = s->map_Data[s->my - 1][s->mx - 1]; s->map_Data[s->my - 1][s->mx - 1] = 0; s->mx++; } } //扫描并确定目标点坐标和我的坐标 void Scanning(Guan_Ka *&s) { int i = 0, n = 0; s->p_Now=0; for (i = 0; i Kuan; i++) { for (n = 0; n Chang; n++) { if (s->map_Data[i][n] == 4 || s->map_Data[i][n] == 2) { s->X1[s->p_Now] = n; s->Y1[s->p_Now] = i; s->p_Now++; } if (s->map_Data[i][n] == 5) { s->mx = n + 1; s->my = i + 1; } } } s->p_Zong = s->p_Now; } // 判断目标点还有几个和纠正目标点 int pass_Ok(Guan_Ka *&s) { s->p_Now = s->p_Zong; for (int i = 0; i p_Zong; i++) { //当目标点变成空地的时候恢复目标点该有的样子 if (s->map_Data[s->Y1[i]][s->X1[i]] == 0) { s->map_Data[s->Y1[i]][s->X1[i]] = 2; } //如果目标点坐标上面有箱子那么目标点就减一 if (s->map_Data[s->Y1[i]][s->X1[i]] == 4 || s->map_Data[s->Y1[i]][s->X1[i]] == 3) { s->p_Now--; } } return s->p_Now; } //显示推箱子关卡 void display_Level(Guan_Ka *&s) { int i = 0, n = 0, z = 0; for (i = 0; i Kuan; i++) { for (n = 0; n Chang; n++) { switch (s->map_Data[i][n]) { //不同的数据表示了不同的形状 case 0: printf(" "); break; case 1: printf("█ "); break; case 2: printf("□"); break; case 3: case 4: for (z = 0; z p_Zong; z++) { if (i == s->Y1[z] && n == s->X1[z]) { printf("\033[31m■\033[37m"); break; } } if (z >= s->p_Zong) { printf("\033[33m■\033[37m"); } break; case 5: for (z = 0; z p_Zong; z++) { if (i == s->Y1[z] && n == s->X1[z]) { printf("\033[31m★\033[37m"); break; } } if (z >= s->p_Zong) { printf("★"); } break; } } printf("\n"); } } Tui_Xiang_Zi.cpp #include "Tui_Xiang_Zi.h" //关卡选择界面 void operation_Interface(int n) { switch (n) { case 1: printf("-------------------\n"); printf(" 欢迎来到推箱子游戏\n"); printf(" 请选择关卡\n"); printf(" 01-26关\n"); printf("-------------------\n"); break; case 2: printf("-------------------\n"); printf(" \033[31m 输入关卡有误\033[37m\n"); printf(" 请重新输入\n"); printf(" 01-26关\n"); printf("-------------------\n"); break; } } int main() { //初始化窗口 system("mode con cols=51 lines=15"); int n = 1, i = 1; char a[2] = {'0', '1'}; Guan_Ka *guan; operation_Interface(1); Initialization(guan); scanf("%s", a); while(read_Guan_ka(a, guan) == 0){ system("cls"); operation_Interface(2); scanf("%s", a); } while (n) { again: system("cls"); if (read_Guan_ka(a, guan) == 0) { printf("\033[33m恭喜你已经通关\033[37\n"); break; } Scanning(guan); // for(int i=0;iKuan;i++) // for (int n = 0; n < guan->Chang; n++) // { // printf("%d",guan->map_Data[i][n]); // } i = 1; while (i) { if (pass_Ok(guan) == 0) { printf("第%c%c关\n", a[0], a[1]); display_Level(guan); printf("即将下一关\n"); sleep(1); break; } else { printf("第%c%c关\n", a[0], a[1]); display_Level(guan); printf("重新开始请按0\n退出请按1\n "); } int b; b = _getch(); switch (b) { case 72: up(guan); break; case 75: left(guan); break; case 77: right(guan); break; case 80: down(guan); break; case '0': goto again; case '1': goto tuichu; } system("cls"); } if (a[1] == 57) { a[0]++; a[1] = 48; } else { a[1]++; } } tuichu: free(guan); printf("游戏结束按任意键退出\n"); getch(); } 关卡数据

下面的需要创建一个txt文件，然后每一个txt文件里面就放一串下面的数字，该文件需要放在同一目录下

// 后两位的数字是关卡数 // Tui_Xiang_Zi01.txt 08080011100000121000001011111113032112035111111131000001210000011100 // Tui_Xiang_Zi02.txt 0909111110000150010000103310111103010121111011121011000021010001001010001111011111000 // Tui_Xiang_Zi03.txt 10070111111100010000011111311100011050300301102210301111221000100111111110 // Tui_Xiang_Zi04.txt 0608011110110010153010113011110301123001122421111111 // Tui_Xiang_Zi05.txt 08080111110001001110015300101110101112101001123001011200030111111111 // Tui_Xiang_Zi06.txt 131100011111110001111000001000100021110100010101000011001010303120100101004001010010213030101001100001010111010111200005101000001100010111111111111 // Tui_Xiang_Zi07.txt 100800011111110011001051001000100100130303010010311001111030101112222200101111111110 // Tui_Xiang_Zi08.txt 10070001111110011100001011203110111223030051122030301111111100100000011110 // Tui_Xiang_Zi09.txt 1109011111111100100110001001000300010013011103100101222101011012221011103003003011000001050111111111111 // Tui_Xiang_Zi10.txt 080700111111001000011113330115032201103222111111001000011110 // Tui_Xiang_Zi11.txt 1206011110011111110010010001103011113001100322220301110000105011011111111110 // Tui_Xiang_Zi12.txt 080700111110111005101003201110023201111043010010001100111110 // Tui_Xiang_Zi13.txt 08080011110000122100011021100100321011030011100133011005000111111111 // Tui_Xiang_Zi14.txt 080711111111100100011032230115324011103223011001000111111111 // Tui_Xiang_Zi15.txt 080701111111110000101030330112222221103303011110511100111100 // Tui_Xiang_Zi16.txt 1009001111110000100001110010300001111030110312220300011222313011111101030100010050010001111111 // Tui_Xiang_Zi17.txt 0907111111000100001000103331100100122111110022301010500001011111111 // Tui_Xiang_Zi18.txt 1009001111111100100012010110032221010030142111011310111000300301100010000111111115010000001111 // Tui_Xiang_Zi19.txt 100801111111000122220100111222311110031303011033001301100001000111110501110001111100 // Tui_Xiang_Zi20.txt 070811111111223221122122110333011003001103330110015011111111 // Tui_Xiang_Zi21.txt 11080001111110000010222100111122221001001113011110303003301150303000011000111000111111011111 // Tui_Xiang_Zi22.txt 0909111111110100000010101330010102221010112223011010110301013003001010010051011111111 // Tui_Xiang_Zi23.txt 100800111111001110001111100030300110300030511113311111001002210000122221000011111100 // Tui_Xiang_Zi24.txt 1409111111000111111000011101002110030301012221101003011100211003330003052111100300310021001003130122210011000001002100011111111111 // Tui_Xiang_Zi25.txt 111000000111111011111200010100122110101003220001010010210111110113100110300003301101310010011500111111111111000000 // Tui_Xiang_Zi26.txt 1312011111111100001000110011110103000000001011311101100101001104010110103222222010110111020101010000031113101000100003510111113101111000001000100000000111110000 // Tui_Xiang_Zi27.txt // Tui_Xiang_Zi28.txt // Tui_Xiang_Zi29.txt // Tui_Xiang_Zi30.txt 我不想写了你们自己搞下面我会给个网址你们自己去写吧哎哟喂

大家可以到这个网址去找推箱子的关卡推箱子关卡大全没错就是4399 后面我再写一个专门用作关卡生成的exe 你们就先手动打着或者改动代码

关卡数据规则

前两位表示x(长) 第3位和第4位表示y(高)后面的数据需要按照这个长和高来定制 5表示玩家 2 表示箱子的目标位置 3表示箱子 4表示箱子是否处于目标位置

思路和建议

其实这不是真正意义上的C语言，而是c++，因为我使用了引用(因为这是我大一的时候写的但是我不想改了引用属实是完全没必要) 但是这里我提供了一些思路你也可是使用指向指针的指针关卡可以读取

建议

大家如果打开看的话一定会发现关卡数是固定的，实际上是我不想写预读取关卡数各位可以根据Tui_Xiang_Zi关卡数.txt这种格式进行一个循环预读取然后重新把到底有多少关渲染上去。

你们仔细的话还会发现一个问题就是第一关我输入01是错的，你们可以写个过滤器

还有一个你们一定觉得这关卡就单纯的看着123450 看起来很打脑壳自己设置关卡的时候肯定会眼睛晕建议写一个专门用于添加关卡的程序可以在同目录下生成Tui_Xiang_Zi关卡数.txt文件 (过段时间我会写一个出来这是今天翻老代码的时候发现了以前写的一个推箱子 )

当然我这雀食有很多不足的地方有些地方的逻辑也没有写好欢迎大家在评论区留言

警告

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