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java如何消除太多的ifelse判断?

#java如何消除太多的ifelse判断?| 来源: 网络整理| 查看: 265

1.简介

if判断语句是很多编程语言的重要组成部分。但是,若我们最终编写了大量嵌套的if语句,这将使得我们的代码更加复杂和难以维护。

让我们看看能否使用别的方式来做呢。

设计模式是为了更好的代码重用性,可读性,可靠性,可维护性,它有六大原则:

单一职责原则(Single Responsibility Principle,简称SRP):该原则是针对类来说的,即一个类应该只负责一项职责. 开放--封闭原则(The Open-Closed Principle简称OCP):是说软件实体(类、模块、函数等等)应该可以扩展,但是不可以修改。 依赖倒转原则(Dependence Inversion Principle :针对接口编程,不要对实现编程 里氏代换原则(Liskov Substitution Principle,简称LSP):里氏代换原则,子类型必须能够替换掉他们的父类型 迪米特法则(Law of Demeter):如果两个类不必彼此直接通信,那么这两个类就不应当发生直接的相互作用 合成/聚合复用原则(Composition/Aggregation Principle],简称CARP):尽量使用合成/聚合,尽量不使用类继承。合成聚合是“has  a”的关系,而继承是“is  a”的关系。 2.示例 if..else public int calculate(int a, int b, String operator) { int result = Integer.MIN_VALUE; if ("add".equals(operator)) { result = a + b; } else if ("multiply".equals(operator)) { result = a * b; } else if ("divide".equals(operator)) { result = a / b; } else if ("subtract".equals(operator)) { result = a - b; } else if ("modulo".equals(operator)) { result = a % b; } return result; } switch-case public int calculateUsingSwitch(int a, int b, String operator) { int result = 0; switch (operator) { case "add": result = a + b; break; case "multiply": result = a * b; break; case "divide": result = a / b; break; case "subtract": result = a - b; break; case "modulo": result = a % b; break; default: result = Integer.MIN_VALUE; } return result; } 3.重构 3.1 工厂方式重构

抽象层Operation.java

public interface Operation { int apply(int a, int b); }

加法实现Addition.java:

public class Addition implements Operation { @Override public int apply(int a, int b) { return a + b; } }

减法实现Subtraction.java

public class Subtraction implements Operation { @Override public int apply(int a, int b) { return a - b; } }

乘法实现Multiplication.java

public class Multiplication implements Operation { @Override public int apply(int a, int b) { return a\*b; } }

除法实现Division.java

public class Division implements Operation { @Override public int apply(int a, int b) { return a / b; } }

求余实现Modulo.java

public class Modulo implements Operation { @Override public int apply(int a, int b) { return a % b; } }

工厂类OperatorFactory.java

import java.util.HashMap; import java.util.Map; import java.util.Optional; public class OperatorFactory { static Map operationMap = new HashMap(); static { operationMap.put("add", new Addition()); operationMap.put("divide", new Division()); operationMap.put("multiply", new Multiplication()); operationMap.put("subtract", new Subtraction()); operationMap.put("modulo", new Modulo()); } public static Optional getOperation(String operation) { return Optional.ofNullable(operationMap.get(operation)); } }

使用示例

public int calculateUsingFactory(int a, int b, String operator) { Operation targetOperation = OperatorFactory .getOperation(operator) .orElseThrow(() -> new IllegalArgumentException("Invalid Operator")); return targetOperation.apply(a, b); } 3.2 枚举方式重构

枚举实现Operator.java

public enum Operator { ADD { @Override public int apply(int a, int b) { return a + b; } }, MULTIPLY { @Override public int apply(int a, int b) { return a * b; } }, SUBTRACT { @Override public int apply(int a, int b) { return a - b; } }, DIVIDE { @Override public int apply(int a, int b) { return a / b; } }, MODULO { @Override public int apply(int a, int b) { return a % b; } }; public abstract int apply(int a, int b); }

封装Operator到Calculator.java

public int calculate(int a, int b, Operator operator) { return operator.apply(a, b); }

使用示例

@Test public void whenCalculateUsingEnumOperator_thenReturnCorrectResult() { Calculator calculator = new Calculator(); int result = calculator.calculate(3, 4, Operator.valueOf("ADD")); assertEquals(7, result); } 3.3 命令模式

抽象的接口

public interface Command { Integer execute(); }

实现类

package com.baeldung.reducingIfElse; public class AddCommand implements Command { private int a; private int b; public AddCommand(int a, int b) { this.a = a; this.b = b; } @Override public Integer execute() { return a + b; } }

其它略包装

public int calculate(Command command) { return command.execute(); }

测试demo

@Test public void whenCalculateUsingCommand_thenReturnCorrectResult() { Calculator calculator = new Calculator(); int result = calculator.calculate(new AddCommand(3, 7)); assertEquals(10, result); } 3.4 规则引擎重构

抽象规则

public interface Rule { boolean evaluate(Expression expression); Result getResult(); }

实现规则AddRule.java 其它略

public class AddRule implements Rule { private int result; @Override public boolean evaluate(Expression expression) { boolean evalResult = false; if (expression.getOperator() == Operator.ADD) { this.result = expression.getX() + expression.getY(); evalResult = true; } return evalResult; } @Override public Result getResult() { return new Result(result); } }

其中:返回结果

public class Result { int value; public Result(int value) { this.value = value; } public int getValue() { return value; } }

表达式

public class Expression { private Integer x; private Integer y; private Operator operator; public Expression(Integer x, Integer y, Operator operator) { this.x = x; this.y = y; this.operator = operator; } public Integer getX() { return x; } public Integer getY() { return y; } public Operator getOperator() { return operator; } }

规则引擎RuleEngine.java

import java.util.ArrayList; import java.util.List; import java.util.Optional; import java.util.stream.Collectors; public class RuleEngine { private static List rules = new ArrayList(); static { rules.add(new AddRule()); } public Result process(Expression expression) { Rule rule = rules.stream() .filter(r -> r.evaluate(expression)) .findFirst() .orElseThrow(() -> new IllegalArgumentException("Expression does not matches any Rule")); return rule.getResult(); } }

测试demo

@Test public void whenNumbersGivenToRuleEngine_thenReturnCorrectResult() { Expression expression = new Expression(5, 5, Operator.ADD); RuleEngine engine = new RuleEngine(); Result result = engine.process(expression); assertNotNull(result); assertEquals(10, result.getValue()); } 4.比较 重构方式 SRP OCP DIP LSP LD CARP IF/ELSE N N N N N N 工厂方法 Y Y Y Y Y Y 枚举方法 N Y Y Y Y Y 命令模式 Y Y Y Y Y Y 规则引擎 Y Y Y Y Y Y 5.小结

  为了更好的代码重用性,可读性,可靠性,可维护性,我们会尝试将IF/ELSE或者case-switch进行改造,使用工厂方法,枚举方法,命令模式,规则引擎方式不同方法进行尝试,最后使用设计模式的六大原则对代码进行评估。

参考资料

【1】https://www.cnblogs.com/davidwang456/p/3641369.html

【2】https://www.baeldung.com/java-replace-if-statements



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