C程序计算矩阵对角线之和

2024-07-10 08:14| 来源: 网络整理| 查看: 265

C程序计算矩阵对角线之和

在这里，我们将用以下3种方法计算矩阵的对角线之和。

1.使用条件语句 2.在使用条件语句的同时从使用r中获取自定义输入 3.使用功能

我们将在上述所有方法中保持相同的输入，并得到相应的输出。

输入:

The matrix is 1 2 3 4 5 6 7 8 9

输出:

Main diagonal elements sum is = 15 Off-diagonal elements sum is = 15

解释：主对角线是1，5，和9。所以，主对角线的总和是1+5+9=15。非对角线是3、5和7。所以，主对角线之和是3+5+7=15。

方法1：条件性语句 // C Program to demonstrate the // Sum of Diagonals of a Matrix #include int main() { int i, j, m = 3, n = 3, a = 0, sum = 0; // input matrix int matrix[3][3] = { { 1, 2, 3 }, { 4, 5, 6 }, { 7, 8, 9 } }; // if both rows and columns are equal then it is // possible to calculate diagonal sum if (m == n) { // printing the input matrix printf("The matrix is \n"); // iterates number of rows for (i = 0; i < m; ++i) { // iterates number of columns for (j = 0; j < n; ++j) { printf(" %d", matrix[i][j]); } printf("\n"); } for (i = 0; i < m; ++i) { // calculating the main diagonal sum sum = sum + matrix[i][i]; // calculating the off diagonal sum a = a + matrix[i][m - i - 1]; } // printing the result printf("\nMain diagonal elements sum is = %d\n", sum); printf("Off-diagonal elements sum is = %d\n", a); } else // if both rows and columns are not equal then it is // not possible to calculate the sum printf("not a square matrix\n"); return 0; }

输出

The matrix is 1 2 3 4 5 6 7 8 9 Main diagonal elements sum is = 15 Off-diagonal elements sum is = 15 方法2：从用户那里获取输入矩阵 // C Program to Demonstrate the Sum of Diagonals // of a Matrix by taking input from the user #include int main() { int i, j, m = 3, n = 3, a = 0, sum = 0; int matrix[10][10]; // if both rows and columns are equal then it is // possible to calculate diagonal sum if (m == n) { // entering the coefficients of the matrix for (i = 0; i < m; ++i) { for (j = 0; j < n; ++j) { scanf("%d", &matrix[i][j]); } } // printing the input matrix printf("The matrix is \n"); // iterates number of rows for (i = 0; i < m; ++i) { // iterates number of columns for (j = 0; j < n; ++j) { printf(" %d", matrix[i][j]); } printf("\n"); } for (i = 0; i < m; ++i) { // calculating the main diagonal sum sum = sum + matrix[i][i]; // calculating the off diagonal sum a = a + matrix[i][m - i - 1]; } // printing the result printf("\nMain diagonal elements sum is = %d\n",sum); printf("Off-diagonal elements sum is = %d\n", a); } else // if both rows and columns are not equal then it is // not possible to calculate the sum printf("not a square matrix\n"); return 0; }

输出:

The matrix is 1 2 3 4 5 6 7 8 9 Main diagonal elements sum is = 15 Off-diagonal elements sum is = 15 方法3：使用函数 // C Program to demonstrate the Sum of Diagonals // of a Matrix by using functions #include const int max = 10; // Declaration of function int diagonal_sum(int m, int n, int matrix[][max]) { int i, j, a = 0, sum = 0; // if both rows and columns are equal then it is // possible to calculate diagonal sum if (m == n) { // printing the input matrix printf("The matrix is \n"); // iterates number of rows for (i = 0; i < m; ++i) { // iterates number of columns for (j = 0; j < n; ++j) { printf(" %d", matrix[i][j]); } printf("\n"); } for (i = 0; i < m; ++i) { // calculating the main diagonal sum sum = sum + matrix[i][i]; // calculating the off diagonal sum a = a + matrix[i][m - i - 1]; } // printing the result printf("\nMain diagonal elements sum is = %d\n", sum); printf("Off-diagonal elements sum is = %d\n", a); } else // if both rows and columns are not equal then it is // not possible to calculate the sum printf("not a square matrix\n"); } int main() { int m = 3, n = 3; // input matrix int matrix[][10] = { { 1, 2, 3 }, { 4, 5, 6 }, { 7, 8, 9 } }; diagonal_sum(m, n, matrix); return 0; }

输出

The matrix is 1 2 3 4 5 6 7 8 9 Main diagonal elements sum is = 15 Off-diagonal elements sum is = 15

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C程序 计算矩阵对角线之和

C程序计算矩阵对角线之和