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ADAMS转动副摩擦参数设置

2024-07-15 05:39| 来源: 网络整理| 查看: 265

1、GrantHillsStudio鹏哥制作(转载)仅供学习交流,非商业用途!RevoluteJointFriction设置一、RevoluteJointModelJointreactions(FaandFr),bendingmoment(Tr),andtorquepreload(Tprfrc)determinethefrictionaltorqueinarevolutejoint.YoucanturnoffoneormoreoftheseforceeffectsusingswitchesSW1throughSW3.Thejointreactions(FaandFr)(注:图3中FR21和Ff21

2、)areconvertedintoequivalenttorquesusingtherespectivefrictionarm(Rn)(注:图3中p)andpinradius(Rp(注:图3中r).Thejointbendingmoment(Tr)isconvertedintoanequivalenttorqueusingpinradius(Rp)dividedbybendingreactionarm(Rb).Thefrictionaltorque(Tfrict)isappliedalongtheaxisofrotationinthedirectionthattheFRDblockcomput

3、es.图1RevoluteJointModelFaJAESRnSW2SW3图3轴颈摩擦力的确定b-SW1Jointvie1cicityBPFR-1J.J也琐CreepTfRp0.MuDynamicDefinethecoefficientofdynamicfriction.ThemagnitudeofthefrictionalforceistheproductofMuDynamicandthemagnitudeofthenormalforceinthejoint,forexample:Frictionforcemagnitude,F=pNwherep=MuDynamicandN=normalfo

4、rceThedynamicfrictionalforceactsintheoppositedirectionofthevelocityofthejoint.Therangeis0.FrictionArmDefinetheeffectivemomentarmusedtocomputetheaxialcomponentofthefrictiontorque.Thedefaultis1.0,andtherangeis0.BendingReactionArmDefinetheeffectivemomentarmusetocomputethecontributionofthebendingmomento

5、nthenetfrictiontorqueintherevolutejoint.Thedefaultis1.0,andtherangeis0.PinRadiusDefinestheradiusofthepin.Thedefaultis1.0,andtherangeis0.StictionTransitionVelocityDefinetheabsolutevelocitythresholdforthetransitionfromdynamicfrictiontostaticfriction.Iftheabsoluterelativevelocityofthejointmarkerisbelow

6、thevalue,thenstaticfrictionorstictionactstomakethejointstick.Thedefaultis0.1lengthunits/unittimeonthesurfaceofcontactinthejoint,andtherangeis0.MaxStictionDeformationDefinethemaximumdisplacementthatcanoccurinajointoncethefrictionalforceinthejointentersthestictionregime.TheslightdeformationallowsAdams

7、/SolvertoeasilyimposetheCoulombconditionsforstictionorstaticfriction,forexample:Frictionforcemagnitude0.FrictionTorquePreloadDefinethepreloadfrictiontorqueinthejoint,whichisusuallycausedbymechanicalinterferenceintheassemblyofthejoint.Thedefaultis0.0,andtheRangeis0.EffectDefinethefrictionaleffectsinc

8、ludedinthefrictionmodel,eitherStictionandSliding,Stiction,orSliding.Stictionisstatic-frictioneffect,whileSlidingisdynamic-frictioneffect.Excludingstictioninsimulationsthatdontrequireitcangreatlyimprovesimulationspeed.ThedefaultisStictionandSliding.InputForcestoFrictionDefinetheinputforcestothefricti

9、onmodel.Bydefault,alluser-definedpreloadsandjoint-reactionforceandmomentsareincluded.Youcancustomizethefriction-forcemodelbylimitingtheinputforcesyouspecify.Theinputsforatranslationaljointare:PreloadReactionForceBendingMomentFrictionSpecifywhetherornotthefrictionalforcesaretobeInactivecalculatedduri

10、ngaStaticequilibriumorQuasi-staticsimulation.DuringThejointvelocitydeterminestheinstantaneousfrictionregimeforajoint.ThefollowingisablockdiagramofthefrictionregimesavailableinADAMS/Solver.MAGuwrrUN3TVDCiraVDCiraJointFelociiyMAGUNITVKTOEWiThfiskoiLi禅locity劭StaticFiictioii*EE-1t*门p,=|_l(i-g)|1A+$|_LS即

11、图4BlockDiagramofFrictionRegimes三、ADAMS模型分析模型是一个简单的圆柱体,与地面间添加转动副,并添加摩擦。本文采用柔性加载,只考虑稳态时的情况(时间足够长时),具体的模型参数大家下载模型()查看,这里就不再一一论述。孑apin血.j.q暮申野血1-d舖Eqye5wnS*lh出峥lewldteJalM_FilticrJOINTHuE-Mb:|H5静摩琮系扛|4llynamc|D45Fl阳wk两1!鈕M.4由|卄Q幣;議工空SSicisnliElianMakcL段:包:昭孤变逹夏H评台轴匚吐昨划込|值e堆艾触If藩士疫空hEtdiIxqijHrSwd|oo饭叩!军

12、澤力比bftoslIWtdKWMUEkbl*J.SdintH匚anwrJEImiINbIif:HrA加rMekislMEiflGFEre厂wjrgNflrtrridHriIracib-aDunj厂SicFiJUi尿m图5ADAMS模型(施加0.12N.m扭矩)決匸加皿幻fru!跆。皿F-阳h玄frj(LrtS_Ji:irfts_Fifk.ionYe5-iXCOjwIlia1-JF-”-刘5ij图6ADAMS模型(施加0.121N.m扭矩)当模型确定后,如果驱动力矩小于产生的摩擦阻力矩,那么系统仍保持静止,如果大于则圆柱体加速转动。通过Mf=Ff21*r=fv*G*r进行计算,通过p=fv*r,由于转动副半径和摩擦圆半径已知,可计算出fv,则整个系统匀速运动的驱动力矩为0.12N.m附近,因此本文中加载了0.12N.m和0.121N.m两种情况。通过对比发现当驱动力矩大于摩擦阻力矩时,圆柱体逐渐加速;驱动力矩小于摩擦阻力矩时,圆柱体保持静止(稳态)。注意对比图中曲线。-GirmtIZIJJ注意空瞇加变化;KiismDlIe(M150.010tdog.弓1訂si芒讲汕产肥D.图7ADAMS模型(圆柱体具有初始速度)对比两中



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